concentration of nitric acid is 15.5m.prepare 200 ml of 1m nitric acid
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[tex]The number of moles of nitric acid can be obtained by multiplying the molarity with volume
M×V=Moles of HNO3=1000250×2=0.5
The mass of nitric acid can be obtained by multiplying the number of mols with molar mass and dividing with percentage concentration.
∴HNO3 required =0.5×63×70100=45g
Thus 45.0 g conc. HNO3 of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3.
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