Question

Concentrations of three type of milks X, Y and Z are 10%, 20% and 30% respectively. They are mixed in the ratio 2:3:P resulting in a 23% concentrations solution. Find P. (1) 7 (2) 6 (3) 5 (4) 4​

Answer 1

Answer:

Step-by-step explanation:

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✍️ Concentrations of three solutions ... and

40% respectively They are mixed in the

ratio 3 : 5 : x resulting in a solution of 30% ...

the amount of A in the solution is 20×3g=60g

in 100×3g=300​g of water, ... the amount of C

in the solution is 40×xg=40xg in 100×xg=100xg

of water.

Answer 2

Answer:

The amount of A in the solution is 20g in 100g of water,

The amount of B in the solution is 30g in 100g of water,

The amount of C in the solution is 40g in 100g of water.

After mixing

the amount of A in the solution is 20×3g=60g in 100×3g=300g of water,

the amount of B in the solution is 30×5g=150g in 100×5g=500g of water,

the amount of C in the solution is 40×xg=40xg in 100×xg=100xg of water.

So the final solution contains (60+150+40x)g=(210+40x)g of the given substances in (300+500+100x)g=(800+100x)g of water.

So the concentration, which is 30% is,

800+100x

210+40x

=

100

30

⟹2100+400x=2400+300x

⟹100x=300

⟹x=3.

Ans- Option C