Question

concentric circles of radii a and b (a > b) are given. Find the length of the chord of the larger
circle which touches the smaller circle.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

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♡ ↪☛ Thus OC is perpendicular to chord AB and bisects it.

In Right-angled \DeltaACD,

Thus OC is perpendicular to chord AB and bisects it.In Right-angled \DeltaACD,By Pythagoras Theorem,

OA^2 & = OC^2 + CA^2 \\ a^2 & = b^2 + CA^2 \\ CA &= \sqrt{(a^2 - b^2)}

AB = 2CA = 2\sqrt{a^2-b^2}

♡

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