Question

concert negative exponent to positive exponent. (-8/9)‐¹⁰​

Answer 1

Answer:

$\left(\frac{-8}{9}\right)^{-10}\\=\left(\frac{-9}{8}\right)^{10}$

Step-by-step explanation:

$\left(\frac{-8}{9}\right)^{-10}\\=\left(\frac{-9}{8}\right)^{10}$

$By \: exponential \:law:\\\boxed {\left(\frac{a}{b}\right)^{-n}=\left(\frac{b}{a}\right)^{n}}$

Therefore,

$\left(\frac{-8}{9}\right)^{-10}\\=\left(\frac{-9}{8}\right)^{10}$

•••♪

Answer 2

Step-by-step explanation:

by exponential law

( a/b) power -n

=(b/a)+

by reciprocal

for example

(4/5) power -5

=5/4power 5

ok I hope this helps to you

note _ by exponential law

the minus power will be converted into positive integer

it means negative to position integer just reciprocal it and just change negative power to

positive power

thank you