Question

Condition for divisibility by numbers from 2 to 10

Answer 1

for 2 the last digit should be even
for 3, the sum of all the digits should be div. by 3..for four. the last digit should be div. by 4 and 5 the digit end with 0 or 5

Answer 2

The Rule for 2 : Any whole number that ends in 0, 2, 4, 6, or 8 will be divisible by 2.

Example: 456,791,824

The Rule for 4 : If the last two digits of a whole number are divisible by 4, then the entire number is divisible by 4.


Example: 456,791,824
The Rule for 8: If the last three digits of a whole number are divisible by 8, then the entire number is divisible by 8.


Example: 456,791,824

The Rule for 5: Number that are divisible by 5 must end in 5 or 0.


Example: 34,780

The Rule for 10: Numbers that are divisible by 10 need to be even and divisible by 5, because the prime factors of 10 are 5 and 2. Basically, this means that for a number to be divisible by 10, the last digit must be a 0.

Example:23,890

Rule: If the sum of the digits is a multiple of 3

Example : 27,333

Rule: If it is divisible by 2 and by 3

Example:24,36

Rule: If the sum of the digits are a multiple of 9

Example :18,27