Math, asked by aswathikv2004, 9 months ago

condition for existence of Laplace transform​

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Answered by kyleschamp
2

Answer:

f is piecewise continuous on the interval 0 ≤ t ≤ A for any A > 0. order”, i.e. its rate of growth is no faster than that of exponential functions.) Then the Laplace transform, F(s) = L{f (t)}, exists for s > a. Note: The above theorem gives a sufficient condition for the existence of Laplace transforms.

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