Question

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Answer 1

Explanation:

1st

Energy consumed by the 20 bulbs in one day= (number of bulbs × power × hours of consumption) = 20 x 100 x 6 = 12,000 Wh

For Fan,

Given I = 0.5 A and V = 220 V

So, Power = Current × voltage = 0.5 × 220 = 110 Wh

Energy consumed by the 10 fans in one day = 10 × 110 × 6 = 6600 Wh

For Electric kettle

Given R = 100 Ohms and V = 220 V Using Ohms Law = I = V/R Amp   therefore, I = 220 V/100 Ohms = 2.2 Amp

So, Power = Current × voltage = 2.2 × 220 = 484 Wh

Energy consumed by the 1 electric kettle in one day = 1 × 484 × 6 = 2904 Wh

Total energy consumption in one day = (12000 + 2904 + 6600)Wh = 21,504 W-h

Total energy consumption in the month of November (30 days) = 30 × 21,504 = 654,120 W-h = 654.12 kW-h = 654.12 units

So, the cost will be 654.12 × 1.8 = Rs 1177.416

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.2nd

◆ Answer -

Energy consumption per month = 516 units

Electricity bill per month = ₹ 1032

● Explanation -

Energy consumed by bulbs is -

Eb = n × P × t

Eb = 20 × 100 × 6×24

Eb = 288000 Wh

Eb = 288 kWh

Energy consumed by fans is -

Ef = n × V × I × t

Ef = 10 × 220 × 0.5 × 6×24

Ef = 158400 Wh

Ef = 158.4 kWh

Energy consumed by electric kettle is -

Ek = V² × t / R

Ek = 220² × 6×24 / 100

Ek = 69696 Wh

Ek = 69.696 kWh

Total energy consumption is calculated by -

E = Eb + Ef + Ek

E = 288 + 158.4 + 69.7

E = 516.1 kWh/month

Total electricity bill per month will be -

Bill = E × cost

Bill = 516 × 2

Bill = ₹ 1032 /month

Therefore, electricity bill will be ₹ 1032 per month.