Question

Conditional Sample

main()

{ int a-300,b=200,c;

if(!a>-200) b=300;

C-400;

printf("b=%d c-%d", b, c);

}

Question Referring to the conditional sample above, what is the output of the program?​

Answer 1

Answer:

Syntex error

Explanation:

i think there would be Syntex error cause that if condition looks wrong to me but it also depends on language.

Answer 2

Answer: Syntax error

Explanation: As the output of the given program is

prog.c:1:1: warning: return type defaults to ‘int’ [-Wimplicit-int]

   1 | main()

     | ^~~~

prog.c: In function ‘main’:

prog.c:3:8: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘-’ token

   3 | { int a-300,b=200,c;

     |        ^

prog.c:3:13: error: ‘b’ undeclared (first use in this function)

   3 | { int a-300,b=200,c;

     |             ^

prog.c:3:13: note: each undeclared identifier is reported only once for each function it appears in

prog.c:3:12: warning: left-hand operand of comma expression has no effect [-Wunused-value]

   3 | { int a-300,b=200,c;

     |            ^

prog.c:3:19: error: ‘c’ undeclared (first use in this function)

   3 | { int a-300,b=200,c;

     |                   ^

prog.c:3:18: warning: left-hand operand of comma expression has no effect [-Wunused-value]

   3 | { int a-300,b=200,c;

     |                  ^

prog.c:5:5: error: ‘a’ undeclared (first use in this function)

   5 | if(!a>-200) b=300;

     |     ^

prog.c:7:1: error: ‘C’ undeclared (first use in this function)

   7 | C-400;

     | ^

prog.c:9:1: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration]

   9 | printf("b=%d c-%d", b, c);

     | ^~~~~~

prog.c:9:1: warning: incompatible implicit declaration of built-in function ‘printf’

prog.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’

 +++ |+#include <stdio.h>

   1 | main()

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