Question

Conduct a cross between a pea plant with round seed and wrinkled seed?​

Answer 1

Explanation:

When the pea plant with yellow and round seeds (YYRR) is crossed with a pea plant having green and wrinkled (yyrr) seeds, the phenotypic ratio is obtained as 9:3:3:1.

There is a total of 320 seeds produced out of which 180 have some phenotype.

There are total of 16 chambers in the Punnett square. So, 320/16=20. There are 20 seeds in one chamber.

If there are 180 seeds that have the same phenotype, these seeds are present in the 180/20=9 chambers. So, the seeds will have the phenotype as yellow and round seeds

Answer 2

Answer:

refer the above pictures...

Explanation:

THE PICTURES WHICH I HAVE HAVE ATTACHED READ THOSE CAREFULLY AND WITH CONCENTRATION YOU WILL GET BOTH ANSWERS AND EXPLANATIONS.....

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