Conduct a triangle ABC in Which BC =4.7cm,angle B=60degree and AB+BC=8.2cm.
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☆☆☆Follow the given steps to
constant the ΔABC....!!!
#Step 1: Draw a line segment BC = 4.7 cm
#Step 2: At B, draw an angle of 60°, say ∠XBC.
#Step 3: Cut a line segment, BD = 8.2 cm (= AB + BC) on the ray BX.
#Step 4: Join DC. Draw ∠DCY = ∠BDC. Let CY intersect BX in A.
》》》The figure in Picture 《《《
●○●Hence, ΔABC is the required triangle. ^_^
constant the ΔABC....!!!
#Step 1: Draw a line segment BC = 4.7 cm
#Step 2: At B, draw an angle of 60°, say ∠XBC.
#Step 3: Cut a line segment, BD = 8.2 cm (= AB + BC) on the ray BX.
#Step 4: Join DC. Draw ∠DCY = ∠BDC. Let CY intersect BX in A.
》》》The figure in Picture 《《《
●○●Hence, ΔABC is the required triangle. ^_^
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