Conducting sphere of radius 5 cm and 10 cm are given a charge of 15 new each after connecting the spirit by copper wire
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The charge transfer is q = 25 μC and Common potential 9×10^6 volts.
Explanation:
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the radii of two charged metallic spheres are 5 cm and 10 cm . each has a charge of 75 micro coulomb. they are connected by a conducting wire . calculate:
1. common potential of the spheres after connecting
2. amount of charge transferred
Initial potential v1 = kQ1/r1
v2 = kQ2/r2
Let the charge transferred = q
Common potential = v
- Charge transfer from one metal to other continues until they both acquire the same potential.
V = K(Q−q)/r1 = k(Q+q)/r2
V = 75 x 10^-6 - 1/ 5 = 75 x 10^-6 +q /10
q = 25 μC
- Common potential = V = 9×10^9×(75−25)×10^−6/5×10^−2
V = 9×10^5×50/5 = 9×10^6 volts
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