Question

Conducting sphere of radius 5 cm and 10 cm are given a charge of 15 new each after connecting the spirit by copper wire

Answer 1

The charge transfer is q = 25 μC and Common potential 9×10^6 volts.

Explanation:

Correct statement

the radii of two charged metallic spheres are 5 cm and 10 cm . each has a charge of 75 micro coulomb. they are connected by a conducting wire . calculate:

1. common potential of the spheres after connecting

2. amount of charge transferred

Initial potential v1 = kQ1/r1

v2 = kQ2/r2

Let the charge transferred = q

Common potential = v

• Charge transfer from one metal to other continues until they both acquire the same potential.

V = K(Q−q)/r1 = k(Q+q)/r2

V = 75 x 10^-6 - 1/ 5 = 75 x 10^-6 +q /10

q = 25 μC

• Common potential = V = 9×10^9×(75−25)×10^−6/5×10^−2

V = 9×10^5×50/5 = 9×10^6 volts

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