Chemistry, asked by hardik2001soni, 4 months ago

Conductivity
(3) Cell constant =
Conductance
(4) Conductance = specific conductivity * cell constant
From the following molar conductivities at infinite dilution,
Am for Al2(SO4)3 = 858 S cm2 mol-1
B
Am for NH,OH = 238.3 S cm mol-1
Am for (NH4)2SO4 = 238.4 S cm2 mot
Calculate Am for Al(OH),
(1) 715.2 S cmmol-1
(3) 786.3 S cm mol
(2) 1575.6 S cm
(4) 157.56 S cm​

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Answered by rathourram
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