Conductivity of 0.00241 M acetic acid is 7.96x10°S cm-'.Calculate its molar conductivity if
foracetic acid is 390.5 S cm' mol-.What is its dissociated constant.
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Answer:
Your answer is:
1.86 x 10^-5
Explanation:
Molar conductivity = K x 1000 /molarity
= 7.96x1000x10^-5 / 0.00241
= 32.76 cm²/mol
alfa= molar conductivity / foracetic acid
= 32.76/390.5
= 8.4 x 10-²
Dissociated constant (Ka)= (0.00241) x (8.4 x 10-²) /1- 8.4 x 10-²
Ka = 1.86 x 10^-5
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