Math, asked by gracidarms40peacn3, 6 months ago

Congruence of triangle class 7
Please explain with steps

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Answers

Answered by kurshitabdulgmailcom
1

Answer:

1. Triangle ABD ~ Triangle ACD

2. Triangle PQS ~ Triangle PRS

Step-by-step explanation:

1.By applying SSS congruency,

AB = AC

BD = CD

Also AD is the dividing part.

Therefore, Triangle ABD ~ Triangle ACD

2. By applying SSS congruency,

PQ = QR

QS = Rs

Also, PS is the dividing part.

Therefore, Triangle PQS ~ Triangle PRS

Answered by nn1710447
0

Answer:

  1. >ywhs
  2.  { =  = 5 \times 3 \times . \sqrt[6 \frac{.60596 = .6 +  +  \div 05 \sqrt[22 <  \sqrt[45 \sqrt[ \gamma  \gamma \%\%]{?} ]{?} ]{?} }{?} ]{?}  \gamma  \binom{ log( \binom{ \gamma  log( \\  \\  \cot( log( \tan( ln(\pi ln(\%\% \times 8y - ) ) ) ) ) ) }{?} ) }{?} }^{ \infty ?} )6(xyy.. \times 5 \times  +  - .014411001 = 576 \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}
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