Congruence:please solve the question above its from congruence of triangle....
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AAS is the answer of this question
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In ΔOAP and ΔOBQ,
∠POA = ∠QOB (Vertically opposite angles)
∠A = ∠B = 90°
AP = BQ
∴ΔOAP ≡ ΔOBQ by AAS congruence rule.
⇒By CPCT,
OA = OB.
∠POA = ∠QOB (Vertically opposite angles)
∠A = ∠B = 90°
AP = BQ
∴ΔOAP ≡ ΔOBQ by AAS congruence rule.
⇒By CPCT,
OA = OB.
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