conill,
2 Construct AABC in which BC=45cm, 8-500, the sum of other side
15 8cm
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Answered by
0
Step-by-step explanation:
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Answered by
4
Step-by-step explanation:
sorry I was not having copy so I have not drawn it
Justification:-
After drawing ΔDBC with BC=4.5cm, ∠B=45
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and DB=8cm. The perpendicular bisector of DC is drawn and it intersects DB at A.
So, we get AC=AD
BD=8cm
⇒BA+AD=8cm
⇒AB+AC=8cm
Hence ΔABC is the required triangle.
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