English, asked by krsubin2003, 5 months ago

conjugate of 1/-2+3i​

Answers

Answered by jadu91
1

Answer:

Conjugate of - 1/2+3i

=

 \sqrt{( -  \frac{1}{2}) {}^{2}  + 3 {}^{2}  }  \\  =  \sqrt{ \frac{1}{4} + 9 }

Answered by sourashtriyaprakash6
0

Answer:

Conjugate of - 1/2+3i

=

\begin{gathered}\sqrt{( - \frac{1}{2}) {}^{2} + 3 {}^{2} } \\ = \sqrt{ \frac{1}{4} + 9 }\end{gathered}

(−

2

1

)

2

+3

2

=

4

1

+9

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