Question

,
Connected
Three resistors
of resistances 20h
40 n and 60 n are
in parallel
find the equivalent resistance
Combination.​

Answer 1

Answer:-

• .R1=20ohm
• R2=40ohm
• R3=60ohm

We know that

$\boxed{\sf \dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}$

$\\ \sf\longmapsto \dfrac{1}{R_{eq}}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{60}$

$\\ \sf\longmapsto \dfrac{1}{R_{eq}}=\dfrac{6+3+2}{120}$

$\\ \sf\longmapsto \dfrac{1}{R_{eq}}=\dfrac{11}{120}$

$\\ \sf\longmapsto {R_{eq}}=\dfrac{120}{11}$

$\\ \sf\longmapsto {}{R_{eq}}=10.9\Omega$