Question

Connie has a number of gold bars, all of different weights. She gives the 24 lightest bars, which weigh 45% of the total weight, to Brennan. She gives the 13 heaviest bars, which weigh 26% of the total weight, to Maya. She gives the rest of the bars to Blair. How many bars did Blair receive?
A.14
B.15
C.16
D.17

Answer 1

______✨ HEY MATE ✨______

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SOLUTION :-
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The average weight of the bars given to Brennan (light) < the average weight of the bars given to Blair < the average weight of the bars given to Maya (heavy).
Let the total weight of all the bars be X.
The weight of the bars given to Brennan,
= 45% of X = 0.45X
The weight of the bars given to Maya,
= 26 % of X = 0.26X
The weight of the bars given to Claire = rest = 29% of X = 0.29X
The average weight of the bars given to Brennan,
= Weight / number of bars = 0.45X/24
The average weight of the bars given to Maya = Weight / number of bars = 0.26X/13
Similarly, if the number of bars given to Blair = B,
then the average weight of the bars given to Blair = 0.29X/B
As, the average weight of the bars given to Brennan (light) < the average weight of the bars given to Blair < the average weight of the bars given to Maya.

So , Option (B) is the right answer ✔️

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Answer 2

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Connie has a number of gold bars, all of different weights. She gives the 24 lightest bars, which weigh 45% of the total weight, to Brennan. She gives the 13 heaviest bars, which weigh 26% of the total weight, to Maya. She gives the rest of the bars to Blair. How many bars did Blair receive?
A.14
B.15
C.16
D.17


$<big><u><b><p>$The average weight of the bars given to Brennan (light) < the average weight of the bars given to Blair < the average weight of the bars given to Maya (heavy).
Let the total weight of all the bars be X.
The weight of the bars given to Brennan,
= 45% of X = 0.45X
The weight of the bars given to Maya,
= 26 % of X = 0.26X
The weight of the bars given to Claire = rest = 29% of X = 0.29X
The average weight of the bars given to Brennan,
= Weight / number of bars = 0.45X/24
The average weight of the bars given to Maya = Weight / number of bars = 0.26X/13
Similarly, if the number of bars given to Blair = B,
then the average weight of the bars given to Blair = 0.29X/B
As, the average weight of the bars given to Brennan (light) < the average weight of the bars given to Blair < the average weight of the bars given to Maya