Math, asked by narcoshanda, 1 month ago

conrruct a Quadrilateral abcd in which ab= 6.5cm ,bc= 5.5cm,da= 3.8cm <a= 90° and < b = 70 °

Answers

Answered by mohanspandit001
0

Answer:

Given:

AB = 6.5 cm, AD = 5 cm, CD = 5 cm, ∠BAC = 40∘ and ∠ABC = 50∘.

Steps for construction:

Step 1 : Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment AB=6.5 cm.

Step 3 : At A on AB make ∠BAXwhose measure is 40∘ and at B on AB make ∠ABYwhose measure is 50∘ . They meet at C.

Step 4 : With A and C as centres draw two arcs of radius 5 cm and let them cut at D.

Step 5 : Join AD and CD. ABCD is the required quadrilateral.

Step 6 : From D draw DE⊥AC and from B draw BC⊥AC. Then measure the lengths of BC and DE. BC=h1=4.2  cm,DE=h2=4.3 cm and AC=d=5 cm.

Calculation of area:

In the quadrilateral ABCD, d=5 cm,h1=4.2 cm and h2=4.3 cm.

Area of the quadrilateral ABCD = 21d(h1+h2)

                                               =21(57.8)(4.2+4.3)

                                               =

Answered by paramjit1977bhullar
0

Step-by-step explanation:

this is the right answer and please mark me brainlist

Attachments:
Similar questions