consecutive even integers whose sum is 162
Answers
Answered by
23
Let the first number be 'x'. Then second number becomes 'x+2'(because the numbers are consecutive and even).
x + (x+2) = 162
x + x +2 = 162
2x + 2 = 162
= 162-2
2x = 160
x = 160/2
= 80
Therefore the first number is 80 and second number is 82.
Favaz003:
2x = 162-2*
Answered by
1
Given:
The sum of two consecutive even integers is 162.
To Find:
The two numbers are?
Solution:
The given problem can be solved using simple algebra.
1. Let the first even integers be x.
2. As every consecutive even integer differ by 2, the next even integer which is consecutive to x is x + 2.
3. The sum of the two consecutive even integers is 162.
=> x + x + 2 = 162,
=> 2x + 2 = 162,
=> 2x = 162 - 2,
=> 2x = 160,
=> x = 160/2,
=> x = 80.
4. The integers are 80 and 82.
Therefore, the integers are 80 and 82.
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