Math, asked by srsudheer1977, 8 months ago

consecutive multiples of 11 is ........​

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Answered by sukhman256
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These are consecutive multiple of 11....

Consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

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