Question

consecutive numbers after 5,10,999

Answer 1

5,11,000 and so on such as 5,11,001 & 5,11,002

Answer 2

Let n = the first consecutive number.
Let n + 1 = the second consecutive number.
Let n + 2 = the third consecutive number.
Let n + 3 = the fourth consecutive number.
Let n + 4 = the fifth consecutive number.

Since the sum of these 5 consecutive number is 100, we can write the following equation:

n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 100
n + n + 1 + n + 2 + n + 3 + n + 4 = 100

Using the Commutative Property of Addition (a + b = b + a) several times, we get:

n + n + n + n + n + 1 + 2 + 3 + 4 = 100

Collecting like-terms on the left side, we have:

5n + 10 = 100

Now, subtracting 10 from both sides, we get:

5n + 10 - 10 = 100 - 10
5n + 0 = 90
5n = 90

Now, dividing both sides by 5 in order to solve for n:

5n/5 = 90/5
(5/5)n = 90/5
(1)n = 18
n = 18

Therefore, ...
n + 1 = 18 + 1 = 19
n + 2 = 18 + 2 = 20
n + 3 = 18 + 3 = 21
n + 4 = 18 + 4 = 22

CHECK:
n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 100
18 + 19 + 20 + 21 + 22 = 100
100 = 100

Therefore, the SMALLEST consecutive number is n = 18.