Question

consecutive numbers of an arithmetic sequence is k+1, 2k+1, 13. Then find the value of k?​

Answer 1

Answer:

k = 4

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Answer 2

Since they are in AP....

Diffrence throughout is same....

So,

13-(2k+1) = (2k+1) - ( k+1)

$13 - (2k + 1) = (2k + 1) - (k +1) \\ \\ 13 - 2k - 1 = 2k + 1 - k - 1 \\ \\ 12 - 2k = k \\ \\ 12 = 3k \\ \\ k = \frac{4}{1}$

k= 4