Math, asked by sujakk701, 9 months ago

consecutive numbers of an arithmetic sequence is k+1 ,2k+1, 13 . Find the value of k​

Answers

Answered by sweety1189
1

Answer:

k=4 is the answer

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Answered by ali01110791357
1

Answer:

k = 4

Step-by-step explanation:

13 - (2k + 1) = (2k + 1) - (k + 1)

13 - 2k - 1 = 2k +1 - k - 1

12 - 2k = k

3k = 12

k = 12/3

k = 4

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