Physics, asked by Bhaveshyeole4273, 1 year ago

conservation of energy for free fall of abody

Answers

Answered by MrPerfect0007
1
hello frnd. .
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Consider a mass which is falling vertically under the influence of gravity. We already know how to analyze the speed of this kind of mass. Let us use this knowledge to find expression for the energy preserved during this process. (NB, this is clearly an example of a closed system, which involves only the mass and the gravitational field.) The physics of free fall under gravity has been summarized with three equations (24) - (26). Let us examine these final equations: Suppose that the mass falls from the height, it has an initial velocity, and its final velocity. It is such that in addition to the pure vertical displacement of the masses, and more. Therefore, the previous expression can be rearranged
(123)

The above equation clearly represents a protection law, because of some explanation, because on the left hand only there is the amount of evaluation in the initial height, whereas in the right hand only the amount of evaluation at the last height is the meaning of ek To do (123), let us define the kinetic energy of the masses,..

Answered by Anonymous
1

Important Formulas :


Potential energy U = mgh

Kinetic energy K = 1/2 mv²

Total energy = K + U


At A


U = mgh

K = 0 since v = 0

Total energy = K + U

                     = mgh + 0

                     = mgh


At B

U = m g h

h = h - x

U = mg ( h - x )


K = 1/2 m v²


By laws of motion:

v² = 2 gh

= > v²= 2 gx

K = mgx


K + U = mg( h - x ) + mgx

         = mgh - mgx + mgx

         = mgh


At C

K = 1/2 m v²

  = 1/2 m × 2 gh [ v² = 2 gh ]

  = mgh


U = 0 since h = 0

Hence K + U = mgh + 0

                     = mgh


Observations :


In all cases ,


K + U = mgh

There fore the total mechanical energy remains constant.

This verifies the Law of Conservation of Energy and also proves that the energy of a body during free fall is conserved !

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