conservation of momentum statement numerical problem
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Conservation of momentum is a fundamental law of physics which states that the momentum of a system is constant if there are no external forces acting on the system. It is embodied in Newton's first law (the law of inertia).
Derivation of Conservation of Momentum
Let us consider a situation wherein: a truck of mass m1, velocity u1 and its momentum = m1u1 and a car of mass m2, velocity u2 and its momentum m2u2; are moving in the same direction but with different speeds. Therefore, total momentum=m1u1 + m2u2.
Now suppose the car and truck collide for a short time t, their velocities will change. So now the velocity of the truck and car become v1 and v2 respectively. However, their mass remains the same. Hence, now the total momentum = m1v1 + m2v2
Acceleration of car (a) = (v2–u2)/t
Also, F = ma
F1 = Force exerted by truck on the car
F1 = m2(v2–u2)/t
Acceleration of truck =(v1–u1)/t
F2 = m1(v1–u1)/t and F1 = –F2
m2(v2– u2)/t = –m1(v1– u1)/t
m2v2–m2u2 = –m1v1+m1u1
or m1u1+m2u2 = m2v2+m1v1
hope u can understand..
Derivation of Conservation of Momentum
Let us consider a situation wherein: a truck of mass m1, velocity u1 and its momentum = m1u1 and a car of mass m2, velocity u2 and its momentum m2u2; are moving in the same direction but with different speeds. Therefore, total momentum=m1u1 + m2u2.
Now suppose the car and truck collide for a short time t, their velocities will change. So now the velocity of the truck and car become v1 and v2 respectively. However, their mass remains the same. Hence, now the total momentum = m1v1 + m2v2
Acceleration of car (a) = (v2–u2)/t
Also, F = ma
F1 = Force exerted by truck on the car
F1 = m2(v2–u2)/t
Acceleration of truck =(v1–u1)/t
F2 = m1(v1–u1)/t and F1 = –F2
m2(v2– u2)/t = –m1(v1– u1)/t
m2v2–m2u2 = –m1v1+m1u1
or m1u1+m2u2 = m2v2+m1v1
hope u can understand..
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