Conservative intergers
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Let the first number be (x-1).
For the second number to be consecutive of the first,it should be the exactly next number that comes after (x-1).
That is,(x-1+1)
That gives (x)
So x is the second number.
Now since the summation is given as 37,
we write,
(x-1)+(x)=37
2x-1=37
2x=38
x=19
So the second number is 19.
The first number is (x-1)
That is 19–1
Equals 18
So the numbers (x-1) and (x) are 18 and 19 respectively.
Hence, the two consecutive numbers are 18 and 19.
This is the method to solving this type of problem
If it helps you then mark me as a brainliest or If not then give reply to me..... Hope it helps
For the second number to be consecutive of the first,it should be the exactly next number that comes after (x-1).
That is,(x-1+1)
That gives (x)
So x is the second number.
Now since the summation is given as 37,
we write,
(x-1)+(x)=37
2x-1=37
2x=38
x=19
So the second number is 19.
The first number is (x-1)
That is 19–1
Equals 18
So the numbers (x-1) and (x) are 18 and 19 respectively.
Hence, the two consecutive numbers are 18 and 19.
This is the method to solving this type of problem
If it helps you then mark me as a brainliest or If not then give reply to me..... Hope it helps
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