consider 11,15,19...........327 how many terms are there please give answer i will follow you back and give 5 thanks
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Answer:
11,15,19,.........,327.
First term=a=11.
Common difference=d=a2-a1=15-11=4.
an=a+(n-1)d.
327=11+(n-1)(4).
327=11+4n-4.
327=7+4n.
327-7=4n.
320=4n.
n=320/4.
n=80.
So, there are 80 terms.
I think this is your answer.
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