Question

Consider 3 bowls. Bowl A contains 2 blue balls and 4 red balls; Bowl B contains 8 blue balls and 4 red balls,
Bowl C contains 1 blue ball and 3 red balls. We draw 1 ball from each bowl. What is the probability to draw a blue ball from Bowl A if we know that we drew exactly a total of 2 blue balls?​

Answer 1

Step-by-step explanation:

The probability of the ball is 1/2

if you don't undestand then check it out.

Answer 2

Answer:

Okay the solution to this question goes like this.

This is the question of conditional probabilily which states in this form. P(A/b) "A" here suggests bowl A

"b" suggests ball blue.

now we need two things as per conditional rule of probabilily that is first P(A & b) --》this is for intersection of A and b

and second P(b) --》this for getting two balls.

we can have 3 cases in which we can get two blue balls.

case 1 : blue A, blue B, red C

case 2: blue A, red B, blue C

case 3: red A, blue B, blue C

so P(b) = (1/2×1/8×1/3) + (1/2×1/4×1/1) + (1/4×1/8×1/1)

and P(A & b) = (1/2×1/8×1/3) + (1/2+1/4+1/1) --》 where we get 2 blue balls with bowl A in both cases.

so P(A/b) = P(A & b)/P(b) = 14/17 = 0.824 (do calculation on your calculator plz.)

Hope this helps