Question

consider 3 vessels A B C .if 1/3 rd of water is drawn from A and put into B .now 1/4 th of water is drawn from B and put into C. again 1/10 of water is drawn from C and put in A .now all vessels have remaining 9 litre water .find out the initial quantity of water.​

Answer 1

Answer:

$x + 9= - \frac{1}{3} - \frac{1}{4} + \frac{1}{10}$

$x + 9 = \frac{ - 20 - 15 + 6}{60}$

$x + 9 = \frac{ - 35 + 6}{60}$

$x + 9 = \frac{ - 29}{60}$

$x = \frac{ - 29}{61} + \frac{9}{1} \times \frac{60}{60}$

$x = \frac{ - 29 + 540}{60} \\ x = \frac{519}{60}$

Step-by-step explanation:

therefore initial amount of water is

$\frac{519}{60}$