Math, asked by ashrss5610, 1 year ago

Consider 36 students to be seated such that each row has same number of students as others . If atleast 3 students are to be seated per row and atleast 2 rows have to be there. How many arrangements are possible?

Answers

Answered by navjot499
1
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Answered by MavisRee
1

Answer:

6 arrangements are possible


Step-by-step explanation:

According to question, 3 condition are to be satisfied and they are :


( 1 ) The number of students per row has to be at least 3.

( 2 ) Number of row has to be at least 2.

( 3 ) Equal number of students has to be seated in a row.

The following arrangements will satisfy all 3 conditions.


1: 3 * 12

3 students in a row = 12 rows.


2: 4*9

4 students in a row = 9 rows.


3: 6*6

6 students in a row = 6 rows.


4: 9*4

9 students in a row = 4 rows.


5: 12*3

12 students in a row = 3 rows


6: 18*2

18 students in a row = 2 rows


Now,

Factors of 36 – 1, 2, 3, 4, 6, 9, 12 , 18 and 36.


Aa condition 1 says number of students in each row must be at least 3 and the number of rows is at least 2.


Both the conditions are satisfied for the following factors : 3, 4, 6, 9, 12, 18

So,

Number if arrangements is 6

Hence,

6 arrangements are possible

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