Question

Consider a 10-cm long portion of a straight wire carrying a current of 10 A placed in a magnetic field of 0.1 T making an angle of 53° with the wire. What magnetic force does the wire experience?

Answer 1

The wire experiences the magnetic force of 0.08 N.

Explanation:

Step 1:

Given,

Length of a straight wire, $I=10 \mathrm{cm}$

The flowing electric current via the wire, $I=10 \mathrm{A}$

Magnetic field, $B=0.1 \mathrm{T}$

Angle between the magnetic field and wire, θ = 53Ëš

Step 2:

Magnetic force,

F→ =Il → × B →

Therefore,  

F→ = IlBsinθ

Therefore, F→ = IlBsin53Ëš

$\Rightarrow \mathrm{F}=10 \times 10 \times 10^{-2} \times 0.798 \times 0.1$

$\approx 0.08 \mathrm{N}$

Step 3:

Using Fleming’s left-hand rule, the force direction can be found.

So, the magnetic force’s direction is perpendicular to the magnetic force and the wire.

Answer 2

Answer:

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Explanation:

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