Question

Consider a 2-digit number such that the ten’s digit is twice that of the unit’s digit.Now, if the digits are reversed and the reversed digit number is subtracted from the original number,the result is always divisible by

Answer 1

Answer:

it's always divisible by 3 and 9

Step-by-step explanation:

take 21 for example, as it is the lowest one possible

21's reverse is 12. now, 21 - 12 = 9

now take 42 and 24.

18.

63 and 36 gives 27, and 84 and 48 gives 36.

notice something common?

9, 18, 27 and 36 are the answers, all of them having something in common.

they are all divisible by 3 and 9