Consider a 3-digit integer x with distinct digits. Let y be the integer formed by swapping
x's units and hundreds digits. What is the least prime number that perfectly divides the
absolute difference between x and y?
Answers
Question :- Consider a 3-digit integer x with distinct digits. Let y be the integer formed by swapping x's units and hundreds digits. What is the least prime number that perfectly divides the absolute difference between x and y ?
Solution :-
Let us assume that, 3 digit integer x is abc , where ,
- unit digit = c
- tens digit = b
- hundreds digit = a .
so,
→ x = (100a + 10b + c)
now, we have given that, y is formed by swapping unit digits and hundreds digits of x .
then,
- unit digit = a
- tens digit = b
- hundreds digit = c
so,
→ y = (100c + 10b + a)
therefore,
→ x - y = (100a + 10b + c) - (100c + 10b + a)
→ x - y = 100a - a + 10b - 10b + c - 100c
→ x - y = 99a - 99c
→ x - y = 99(a - c)
→ x - y = 3 * 3 * 11 * (a - c) .
Hence, we can conclude that, the least prime number that perfectly divides the absolute difference between x and y is 3 . {when value of (a - c) is not equal to 2.}
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Given : 3-digit integer x with distinct digits.
y be the integer formed by swapping x's units and hundreds digits.
To Find : the least prime number that perfectly divides the absolute difference between x and y
Solution:
3-digit integer x with distinct digits. = abc
100a + 10b + c
y be the integer formed by swapping x's units and hundreds digits.
=> cba
100c + 10b + a
Difference = 100a + 10b + c - (100c + 10b + a)
= 99a - 99c
= 99(a - c)
= 3 * 3 *11 (a - c)
3 is the least prime number that perfectly divides the absolute difference between x and y
and 2 can b least if | a - c | = 2.
11 is the greatest prime number that perfectly divides the absolute difference between x and y
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