Question

Consider a 32-bit microprocessor that has an on- chip 16-kB four- way set- associative cache. Assume that the cache has a line size of four 32-bit words. Draw a block diagram of this cache showing its organization and how the different address fields are used to determine a cache hit/miss. Where in the cache is the word from memory location ABCDE8F8 mapped?

Answer 1

The set number 62 is the mapped area for the memory location ABCDE8F8.

• A microprocessor is a type of computer processor where the logic and control for data processing are housed on a single integrated circuit or a few interconnected integrated circuits. The arithmetic, logic, and control circuitry needed to carry out the tasks of a computer's central processing unit are all included within the microprocessor.
• The integrated circuit has the ability to understand, carry out, and perform arithmetic operations. The microprocessor is a multifunctional, clock-driven, register-based, digital integrated circuit. It receives binary data as input, processes it in accordance with instructions stored in its memory, and outputs the results (also in binary form). Combinational and sequential digital logic are both present in microprocessors, which use the binary number system to represent numbers and symbols.

Here, according to the given information, we are given that,

A 32-bit microprocessor that has an on- chip 16-kB four- way set associative cache.

Thus, the term "addressing" is used. Thus, for 4 words, offset bits equal 2.

Sets = number of lines/p (way)

$\frac{Cache size}{Line size} =2^{10}$

Sets = $\frac{2^{10} }{4} =256$.

Here, the block diagram can be drawn by putting tag that is 22 bit in the first block, sets that is 8 bit in the second block and block size that is 2 bit in the third box.

Now, the memory location is ABCDE8F8.

Its binary equivalent is 1010 1011 1100 1101 1110 1000 1111 1000.

Hence, the set number 62 is the mapped area for the memory location ABCDE8F8.

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