Question

Consider a 7-digit number N=ABCDE15. If N is divisible by 11 then the maximum value of A+C+E is​

Answer 1

Answer:

The maximum value of A+C+E is​  A+C+E=14

Step-by-step explanation:

For  a  number to be divisible by 11 , the sum of digits in the even  place should be divisible by that in the odd position.

Therefore A+C+E+5=B+D+1

For A+C+E to be maximum the values of B and D should be equal to 9

A+C+E=14