Question

consider a a level memory has average access
time 35 ns with cache and memory access time
as 25 and 155 is respectively. calculate the
hit ratio.
A. 0.84
B. 0.93
C. 0.924
D. 0.885​

Answer 1

Answer:

hey mate, C is correct answer

Explanation:

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Answer 2

Answer:

Hit ratio is 92.3percent

Explanation:

Average memory access time is given by

$</p><p> average \: access \: memory= Hit ratio × access \: time \: in \: cache memory + (1 – Hit ratio) × \: Access \: time \: in \: main memory</p><p>$

Calculation:

Given:

Hit ratio = ? (Let it be h)

Main memory access time = 155ns

Cache memory access time = 25 ns

Average memory access time = 35ns

$35 = h(25) + (1 - h)(155)$

$35 = 25h + 155 - 155h$

$h = \frac{12}{13}$

$hit \: ratio \: = 92.3percnt$

therefore hit ratio is 92.3percent

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