Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00g of fat to fly over a distance db without stopping for feeding. How far will the bird fly before feeding again?
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I think you should have included your fat- and carb-to-energy conversion rates. I'll use
1 g fat = 9 cal = 37.6812 J
1 g carb = 4 cal = 16.7472 J
d = v*t = v * energy / power
d = 10.7m/s * 4g fat * 37.6812J/gfat / 3.70J/s = 436 m ◄ (a)
(b) Since there is 4/9 as much energy per gram of carb, we need 9/4 as much, or 9 grams. ◄
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1 g fat = 9 cal = 37.6812 J
1 g carb = 4 cal = 16.7472 J
d = v*t = v * energy / power
d = 10.7m/s * 4g fat * 37.6812J/gfat / 3.70J/s = 436 m ◄ (a)
(b) Since there is 4/9 as much energy per gram of carb, we need 9/4 as much, or 9 grams. ◄
If you find this helpful, please select Best Answer!
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