Consider a boat which moves at the speed of 6 km/hr. If the water runs at the speed of about 4 km/hr, then the boat requires 3 hours to reach a certain place and return. Calculate the distance between that place and boat's initial position.
Answers
Answered by
1
Explanation:
Distance between two places = [t(x² – y²)]/2x km/h
Given: Speed of boat (x) = 6 km/hr
Speed of water (y) = 4 km/hr
Time taken by the boat to go & return back = t = 3 hrs
To find the distance between the place & initial position of boat (i.e. between two places), we have
D = [t(x² – y²)]/2x
D = [3 x (6² – 4²)]/2(6)
= [3 x (20)] /12
= 60/12
= 5 km/hr
Answered by
0
Answer:
5
Explanation:
speed of boat in still water x=6
speed of stream y=4
Tu +Td = 3
d /2 + d/10 =3
by calculating d=5
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