Question

Consider a body starting from rest and moves with a uniform acceleration of 2 m/s² for 1s. Find its displacement.

Answer 1

Given:

Initial velocity of body, u= 0 m/s

(Since it starts from rest)

Acceleration, a= 2 m/s²

Time taken, t= 1s  

To Find:

Displacement of given body

Solution:

Let the displacement of body be 's' m

We know that,

• According to second equation of motion for uniform acceleration

$\pink{\boxed{\bf{s=ut+\frac{1}{2}at^{2}}}}$

where,

s is displacement of body

u is initial velocity of body

a is acceleration of body

t is time taken by body

Now, for the given body

$\longrightarrow\mathrm{s=ut+\dfrac{1}{2}at^{2}}$

$\longrightarrow\mathrm{s=0(1)+\dfrac{1}{\cancel{2}}(\cancel{2})(1)^{2}}$

$\longrightarrow\mathrm{\green{s=1\:m}}$

Hence, the displacement of given body is 1 m.

Answer 2

Given,

A body starts from rest (i.e. initial velocity, u = 0 m/s)

It moves with a uniform acceleration of 2 m/s² for 1 s. (i.e. acceleration, a = 2 m/s² and time, t = 1 s)

To calculate :

For the displacement of the body.

Answer :-

By the second equation of motion, we get :

$\boxed{\tt{s=ut+\frac{1}{2}at^2 }}$

• Where, 's' represents the displacement, u represents the initial velocity, a represents the acceleration and t represents the time taken.

Now,

putting the known values in the above equation :

$\tt{s=0(1)+\frac{1}{2}*2*(1)^2 }\\\\\tt{\implies s=0+1*1}\\\\\\bold{\underline{\boxed{\boxed{\tt{\implies s=1\ m}}}}}$

∴ So, the body displaces about 1 m from its initial point to its final point.

ADDITIONAL INFO :-

Displacement :- The shortest distance covered between the initial and the final position of the object.

                              OR

It is the change in position vector.