Consider a boy standing on a building that is 500 m height and another boy standing on the ground. If the boy on the ground throws a ball to the boy standing on the building, with what vertical velocity must the ball be thrown such that it reaches the boy standing on the building. Neglect the height of the boys.
Answers
Answer 99m/s
Explanation: kinetic energy of the ball must be equal to potential energy when thrown
1/2 mv^2= mgh
v=sqrt(2gh)
v=sqrt(2x9.8m/sx500m)
=99m/s
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Answer:
The ball must have an equivalent amount of potential energy when it is thrown in order for it to reach the top. So the correct answer would be 99m/s.
Explanation:
What is kinetic energy?
The energy an item has as a result of motion is known as kinetic energy. A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy rises with increasing mass and/or speed, and it stays the same unless an item slows down or accelerates. Translational kinetic energy and rotational kinetic energy are the two basic categories of kinetic energy.
Calculations:
1/2 mv^2= mgh
v=sqrt(2gh)
v=sqrt(2x9.8m/sx500m)
=99m/s
To know more about kinetic energy, check out:
https://brainly.in/question/1797886
To know more about speed, check out:
https://brainly.in/question/18334321
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