Question

consider a car moving along a straight horizontal road with a speed of 72 km/hr . if the coefficient of static friction between road and tyres is 0.5 , the shortest distance in which the car can be stopped is
(a) 30m (b) 40m (c) 72m (d) 20m

Answer 1

(b)

Here u = 72 km/h = 20 m/s; v = 0;  

a =- ?g = -0.5 × 10 =-5m/s2  

As v2 = u1 + 2as,  

? s=  ((v^2- u^2 ))/2a  =((0- (20)^2)/(2× (-5) )=40 m

Answer 2

Explanation:

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