Question

Consider a car moving on a straight road with a
speed of 100 m/s. The distance at which car can
be stopped is hi = 0.5]

Answer 1

Explanation:

μ=100m/s

μ=0.5

g=10/s

2

when car is stopped by friction retarding force is

ma=μR

ma=μmg

a=μg

Let car covers '5' distance with velocity μ and stop

V

2

−4

2

=2aS

4

2

=2aS(V=0)

S=

2a

4

2

=

2×μg

100

2

=

2×0.5×10

100

2

⇒S=1000m