Question

Consider a car moving on a straight road with a speed of 100m/s . the distance at which car can be stopped is *[ μₖ = 0.5]
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Answer 1

Answer:

ANSWER

μ=100m/s

μ=0.5

g=10/s

2

when car is stopped by friction retarding force is

ma=μR

ma=μmg

a=μg

Let car covers '5' distance with velocity μ and stop

V

2

−4

2

=2aS

4

2

=2aS(V=0)

S=

2a

4

2

=

2×μg

100

2

=

2×0.5×10

100

2

⇒S=1000m

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Answer 2

Explanation :-From Newton's equation , we have

• v² = u² -2as
• Given ;- V = 0 (car is stopped )
• As friction proved the retardation
• a = μg , v = 100m/s
• ∴ 100² = 2μgs
• s = 100* 100 / 2 × 0.5× 10
• => s = 100* 100 / 5*2

= 1000 m Answer

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