consider a car moving on a straight road with a speed of 100ms^-1 the distance at which car can be stopped is nu k is 0.5
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Answer:
μ=100m/s
μ=0.5
g=10/s
2
when car is stopped by friction retarding force is
ma=μR
ma=μmg
a=μg
Let car covers '5' distance with velocity μ and stop
V
2
−4
2
=2aS
4
2
=2aS(V=0)
S=
2a
4
2
=
2×μg
100
2
=
2×0.5×10
100
2
⇒S=1000m
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