Consider a circular coil of wire consisting of 200
turns, each of radius 10 * 10-2 m, carrying a
current of 0.2 A.
What is the magnitude of the magnetic field at the
center of the coil?
Answers
Answered by
1
Explanation:
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Answered by
2
Answer:
2.51*10^-4T
Explanation:
no.of turns on the circular coil,n=200
radius of each turn,r=10* 10-2m
current flowing in the coil,I=0.2A
|B|=μo2πnI/4πr
= 4π*10-7*2π*209*0.2/4π*10*10-2
=2.51*10-4T
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