Question

Consider a circular conductor with 2m radius and 8 A current flowing through it. What is
the value of magnetic field intensity at the centre of the circular conductor?

Answer 1

Explanation:

B=10–⁷2πni/r=10-⁷×2π×1×8/2=10–7 ×8π

Answer 2

Given:

A circular conductor with 2m radius and 8 A current flowing through it.

To find:

Magnetic Field Intensity at centre of circular conductor ?

Calculation:

The general expression for field intensity at centre of circular conductor:

$B = \dfrac{ \mu_{0} i}{4\pi r} \times 2\pi$

$\implies B = \dfrac{ \mu_{0} \times 8}{4\pi \times 2} \times 2\pi$

• $\mu_{0}/4\pi$ is equal to 10^(-7).

$\implies B = {10}^{ - 7} \times \dfrac{ 8}{2} \times 2\pi$

$\implies B = 8\pi \times {10}^{ - 7} \: T$

So , field intensity is 8π × 10^(-7) Tesla.