Consider a circular road of radius 10m barked at an angle of 45 degree with what speed a car has to move on the turn so that it will have safe turn? (Take g = 10m/s2)
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Answered by
1
Answer:
The road at a circular turn of radius 10m is banked by an angle of 10 degrees.
Let The speed used by the vehicle to move on the turn so that the normal contact force is v
So v=
r×gtam10
0
v=
10×10×0.18
v=
18
v=3.2m/s
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Answered by
4
Answer:
The road at a circular turn of radius 10m is banked by an angle of 10 degrees.
Let The speed used by the vehicle to move on the turn so that the normal contact force is v
So v=r×gtam100
v=10×10×0.18
v=18
v=3.2m/s
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