Consider a class of 5 girls and 7 boys. The number of different teams consisting of 2 girls and 3 boys that can be formed from this class, if there are two specific boys A and B, who refuse to be the members of the same team, is: (A) 500 (B) 200
(C) 300 (D) 350
[JEE Main 2019]
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300 Different teams can be formed
Step-by-step explanation:
a class of 5 girls and 7 boys.
teams consisting of 2 girls and 3 boys
2 girls can be selected in ⁵C₂ = 10 ways
3 boys can be selected in ⁷C₃ = 35 Ways
Total possible Teams = 10 * 35 = 350
but A & B can not be together
Case when A & B are together
third boy can be selected from remaining 5 boys in 5 way
Total possible teams = 10 * 5 = 50
Possible number of Teams = 350 - 50
= 300
300 Different teams can be formed
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